Asked by COFFEE
How would I solve the following integral with the substitution rule?
Integral of: [(x^3)*(1-x^4)^5]dx
Put 1-x^4 = y
Then -4x^3 dx = dy
Integral is then becomes:
Integral of -1/4 y^5 dy
ok, thanks a lot! I got it now.
Integral of: [(x^3)*(1-x^4)^5]dx
Put 1-x^4 = y
Then -4x^3 dx = dy
Integral is then becomes:
Integral of -1/4 y^5 dy
ok, thanks a lot! I got it now.
Answers
Answered by
jaime
integrals of S 2-4 ((3*y^5)/(5*(y^3 -2)^(1/4)))*dy
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