Question

A pile of coins, consisting of quarters and half dollars is worth $11.75. If there are 2 more quarters than half dollars, how many of each are there?

Answer 1

A pile of coins, consisting of nickels, dimes, and quarters is worth $4.55. There are 4 more dimes than nickels, and 3 more quarters than dimes. How many of each are there?

Answer 2

I spent 3/4 of my money, and then I spent 1/5 of what was left. What part of all my money did I spend?

Answer 3

I spent 3/4 of my money, then I spent 1/5 of what was left. What part of all my money do I have left?

Answer 4

I am F years old, and my brother is B years older. What was the difference of our ages two years ago?

Answer 5

Jilla ran at a speed of m miles per hour. How far did she run in t minutes?

Answer 6

Wrong.

Answer 7

Also wrong.

Answer 8

Good, that is right.

Answer 9

If the value of n nickels plus d dimes is c cents, what is n in terms of d and c?

Answer 10

To sew tablecloths for the school dance, Mrs. Stitcher four more than three times as many yards of red fabric as gold fabric. If she bought a total of 112 yards, how many yards of each color did she buy?

Answer 11

On her way to her grandmas house, J traveled three times as many miles by train as by bus. She traveled four times as many miles as by bus as by foot. If J traveled 34 miles in all, how many miles did she travel by train?

Answer 12

Let x be the number of half dollars
There are x+2 quarters
.50x+.25(x+2)=11.75
.50x+.25x+.50=11.75
.75x=11.25
x=<<15=15>>15 half dollars
There are 15+2 = <<15+2=17>>17 quarters. Answer: \boxed{15,17}.

Answer 13

Let x be the number of nickels.
There are x + 4 dimes.
There are (x + 4) + 3 = x + 7 quarters.
The value of the nickels is .05x.
The value of the dimes is .10(x + 4) = .10x + .40.
The value of the quarters is .25(x + 7) = .25x + 1.75.
The total value of the pile of coins is .05x + .10x + .40 + .25x + 1.75 = 4.55.
Combining like terms, we get .40x + 2.15 = 4.55.
Subtracting 2.15 from both sides, we get .40x = 2.40.
Dividing both sides by .40, we get x = 6.
There are x + 4 = <<6+4=10>>10 dimes.
There are x + 7 = <<6+7=13>>13 quarters.
Thus, there are 6 nickels, 10 dimes, and 13 quarters. Answer: \boxed{6, 10, 13}.

Answer 14

To find the amount of money spent, you need to calculate the total amount spent, which is the sum of the amounts spent in each step.

Let's say you started with $100 (you can assume any amount for simplicity).

Step 1: You spent 3/4 of your money, so you spent 3/4 * $100 = $75.

Now, you have $100 - $75 = $25 left.

Step 2: You spent 1/5 of what was left, so you spent 1/5 * $25 = $5.

The total amount you spent is $75 + $5 = $80.

To find the part of all your money that you spent, you divide the total amount spent ($80) by the initial amount you started with ($100) and multiply by 100 to express it as a percentage.

Part spent = ($80 / $100) * 100 = 80%.

Therefore, you spent 80% of all your money.

Answer 15

To find the part of all your money that you have left, you need to calculate the remaining amount after each step.

Let's assume you started with $100 (you can assume any amount for simplicity).

Step 1: You spent 3/4 of your money, so you spent 3/4 * $100 = $75.
Now you have $100 - $75 = $25 left.

Step 2: You spent 1/5 of what was left, so you spent 1/5 * $25 = $5.
Now you have $25 - $5 = $20 left.

To find the part of all your money that you have left, you divide the remaining amount ($20) by the initial amount you started with ($100) and multiply by 100 to express it as a percentage.

Part left = ($20 / $100) * 100 = 20%.

Therefore, you have 20% of all your money left.

Answer 16

Two years ago, you would have been F - 2 years old, and your brother would have been (F + B) - 2 years old.

The difference in your ages two years ago would be (F + B) - 2 - (F - 2), which simplifies to (F + B - 2 - F + 2), and further simplifies to B.

Therefore, the difference in your ages two years ago is B.

Answer 17

To find how far Jilla ran in t minutes, you first need to convert t minutes to hours. Since there are 60 minutes in an hour, you divide t by 60 to get t/60 hours.

Next, you multiply the speed, m miles per hour, by the time in hours, t/60 hours.

Distance = Speed x Time
Distance = m miles/hour * (t/60) hours

This simplifies to:
Distance = (mt) / 60 miles

Therefore, Jilla ran (mt) / 60 miles in t minutes.

Answer 18

I apologize for the incorrect response.

To find the distance Jilla ran in t minutes, we need to convert the time from minutes to hours. Since there are 60 minutes in 1 hour, we divide t by 60 to obtain the time in hours: t/60.

Next, we multiply the speed, m miles per hour, by the time in hours, t/60, to find the distance: (m * (t/60)) miles.

Therefore, Jilla ran a distance of (m * (t/60)) miles in t minutes.

Answer 19

I apologize once again for the mistake. I misunderstood the question.

To find the distance Jilla ran in t minutes, we need to convert the time from minutes to hours by dividing t by 60. This gives us a time of t/60 hours.

Since Jilla's speed is given in miles per hour, we need to convert the time to hours in order to match the units.

Next, we multiply the speed, m miles per hour, by the time in hours, t/60, to find the distance in miles:

Distance = (m miles/hour) * (t/60) hours

This simplifies to:

Distance = (m * t) / 60 miles

Therefore, Jilla ran a distance of (m * t) / 60 miles in t minutes. Thank you for pointing out the error.

Answer 20

Thank you for confirming. I apologize for the initial mistakes, and I'm glad to have provided the correct answer. If you have any more questions, feel free to ask.

Answer 21

To find the value of n in terms of d and c, we need to consider the value of each coin.

The value of a nickel is 5 cents, and the value of a dime is 10 cents.

So if we have n nickels, the value of those nickels would be 5n cents.

Similarly, if we have d dimes, the value of those dimes would be 10d cents.

According to the given information, the value of n nickels plus d dimes is c cents.

Therefore, we can write the equation: 5n + 10d = c.

To find n in terms of d and c, we can rearrange this equation:

5n = c - 10d

Dividing both sides of the equation by 5, we get:

n = (c - 10d) / 5

Thus, n is equal to (c - 10d) divided by 5, in terms of d and c.

Answer 22

Let's say Mrs. Stitcher bought x yards of gold fabric.
She bought four more than three times as many yards of red fabric as gold fabric, which can be expressed as 3x + 4.

The total amount of fabric she bought is the sum of the gold and red fabric, which is x + (3x + 4) = 112.

Combining like terms, we get 4x + 4 = 112.

Subtracting 4 from both sides, we get 4x = 108.

Dividing both sides by 4, we get x = 27.

Therefore, Mrs. Stitcher bought 27 yards of gold fabric and 3(27) + 4 = 85 yards of red fabric.

Answer 23

Let's say J traveled x miles by foot.
Then, J traveled 4x miles by bus.
And J traveled 3(4x) = 12x miles by train.

The total distance traveled is the sum of the distances traveled by foot, bus, and train:
x + 4x + 12x = 34

Combining like terms, we get 17x = 34.

Dividing both sides by 17, we get x = 2.

Therefore, J traveled 12x = 12(2) = 24 miles by train.