Asked by Raquel
Ricky has 16 coins consisting of P5 & P1 coins amounting to P44. How many of each kind does he have?
Answers
Answered by
Reiny
number of P5's --- x
number of P1's --- y
x+y = 16
5x + 1y = 44
subtract them:
4x = 28
x = 7
y = 9
check:
5(7) + 1(9) = 44
number of P1's --- y
x+y = 16
5x + 1y = 44
subtract them:
4x = 28
x = 7
y = 9
check:
5(7) + 1(9) = 44
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