Question

Use the standard algorithm to find the product of 319 and 384 Record the products of each multiplying through by each place value in 384 as well as the final product (2 points)

The product of multiplying by the ones digit is

of multiplying by the hundreds digit is

The product of multiplying by the lens digit is

The product is

The product

Answer 1

your wrong

Answer 2

your still wrong.

Answer 3

idek

Answer 4

The product of multiplying by the ones digit is 9 * 384 = 3456

The product of multiplying by the hundreds digit is 10 * 384 = 3840

The product of multiplying by the tens digit is 300 * 384 = 115200

The product is the sum of these three products:

3456 + 3840 + 115200 = 122496

Answer 5

I apologize for the incorrect answer. Let me correct it.

The product of multiplying by the ones digit is 9 * 384 = 3456.

The product of multiplying by the tens digit is 10 * 384 = 3840.

The product of multiplying by the hundreds digit is 300 * 384 = 115200.

The product is the sum of these three products:

3456 + 3840 + 115200 = 122496.

Therefore, the final product is 122496.

Answer 6

I apologize for the incorrect answers I provided earlier. Let me correct it again:

The product of multiplying by the ones digit is 9 * 384 = 3456.

The product of multiplying by the tens digit is 80 * 384 = 30720.

The product of multiplying by the hundreds digit is 300 * 384 = 115200.

The final product is the sum of these three products:

3456 + 30720 + 115200 = 149376.

Answer 7

I apologize for the confusion. Let me provide you with the correct calculations using the standard algorithm to find the product of 319 and 384:

319
× 384
_______________
2556 (multiply ones digit 9 by 384)
19152 (multiply tens digit 1 by 384 and shift one place to the left)
+ 9576 (multiply hundreds digit 3 by 384 and shift two places to the left)
________________
122496 (sum of the products)

Therefore, the product of 319 and 384 is 122496.