Asked by s
Use the algorithm for curve sketching to sketch the following:
y= 2x/(x^2-25)
y= 2x/(x^2-25)
Answers
Answered by
oobleck
you know that
there is an x-intercept and a y-intercept at (0,0)
there are two vertical asymptotes at x = -5 and +5
The horizontal asymptote is y=0
type in your function at wolframalpha.com to verify your sketch.
there is an x-intercept and a y-intercept at (0,0)
there are two vertical asymptotes at x = -5 and +5
The horizontal asymptote is y=0
type in your function at wolframalpha.com to verify your sketch.
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