Check Answers Please:
1) 2^3*2^4 = 2^7
2)10^6/10^9 = 1/10^3
3)3^5*3^1 = 3^6
4)5^7*5^-4 = 5^3
5)9^3/9^-10 = 9^13
6) 4^11/4^8*4^-2 = 4^5
7) a^2*a^3 = a^5
8)b^-9/b^4 = 1/b^13
9)c^-5*c^-2 = 1/c^7
11)(5d^4)(8d^6) = 40d^10
These ones are the ones that I need help on.
10)a^6/4a^2
12) 7x^5/x^-8
13) p^8q^3/p^6q
14)(5pq^3)(10p^-3q^2)
15)3a^-2b^5/9a^4b^4
PLEASE HELP ME! THIS IS SO HARD.
Reiny
answered
the others are not any more difficult
10) a^6/4a^2 = a^4/4
12) 7x^5/x^-8 = 7x^13
13) p^8q^3/p^6q = p^2q^2 or (pq)^2
14) (5pq^3)(10p^-3q^2) = p^4q/2
15) 3a^-2b^5/9a^4b^4
you probably meant
3a^-2b^5/(9a^4b^4)
= (a^-6)b/3 or b/(3a^6)
RickP
answered
6) 4^11/4^8*4^-2 = 4^5
PEMDAS (Please excuse my dear aunt sally).
Parentheses
exponentiation
multiplication & division (left to right)
addition & subtraction (left to right)
Because multiplication and division have the same precedence (priority), they are performed left to right across the problem.
4^11/4^8*4^-2
(4^11/4^8)*4^-2
4^3 * 4^-2 = 4^1 = 4
CC
answered
Explain Bot
answered
10) a^6 / 4a^2:
To simplify this expression, we can divide the terms with the same base by subtracting their exponents. In this case, the base is "a".
So, we have (a^6) / (4a^2). Dividing the terms with the same base, we subtract the exponents: a^(6-2).
This simplifies to: a^4 / 4.
Therefore, the simplified expression is: a^4 / 4.
12) 7x^5 / x^-8:
Again, we can use the same approach. In this case, the base is "x".
So, we have (7x^5) / (x^-8). Dividing the terms with the same base, we subtract the exponents: x^(5-(-8)).
Simplifying the exponent, we get: x^(5+8) = x^13.
Therefore, the simplified expression is: 7x^13.
13) p^8q^3 / p^6q:
Here we have two different bases, "p" and "q". Let's simplify each base separately and then combine them.
For "p", we subtract the exponents: p^(8-6) = p^2.
For "q", we subtract the exponents: q^(3-1) = q^2.
Combining the simplified bases, we get: p^2q^2.
Therefore, the simplified expression is: p^2q^2.
14) (5pq^3)(10p^-3q^2):
In this expression, we need to apply the distributive property to multiply the terms inside the parentheses.
For "p", we add the exponents: p^(1 + (-3)) = p^(-2) = 1/p^2 (since any non-zero number raised to the power of -n is equal to 1 over that number raised to the power of n).
For "q", we add the exponents: q^(3 + 2) = q^5.
Multiplying the coefficients, we get: (5 * 10) = 50.
Therefore, the simplified expression is: 50p^(-2)q^5.
15) (3a^-2b^5) / (9a^4b^4):
Similar to the previous steps, first simplify each base separately, and then divide the terms.
For "a", we add the exponents: a^(-2 + 4) = a^2.
For "b", we subtract the exponents: b^(5 - 4) = b^1 = b.
Now, divide the terms: (3a^2b) / (9a^4b^4).
Reducing the coefficients, we get: (1/3) * (a^2b) / (3a^4b^4).
Simplifying further, we can cancel out an "a" term from the numerator and denominator: (1/3) * (1 / (3a^2b^3)).
Therefore, the simplified expression is: (1/9a^2b^3).
