Question
A carpenter is working on a project that calls for three pieces of wood.
The longest piece must be twice the length of the middle-sized piece.
The shortest piece must be 6 inches shorter than the middle-sized piece.
If the three pieces sum to a total of 80 inches, how long must each piece be?
Let x= length of the middle-sized piece
Write an expression involving x for the length of each piece.
Longest piece =
Middle-sized piece =
Shortest piece =
Write an equation taking the sum of the three pieces and solve.
The longest piece must be twice the length of the middle-sized piece.
The shortest piece must be 6 inches shorter than the middle-sized piece.
If the three pieces sum to a total of 80 inches, how long must each piece be?
Let x= length of the middle-sized piece
Write an expression involving x for the length of each piece.
Longest piece =
Middle-sized piece =
Shortest piece =
Write an equation taking the sum of the three pieces and solve.
Answers
GPT 3.5
Longest piece = 2x
Middle-sized piece = x
Shortest piece = x - 6
The equation for the sum of the three pieces is:
2x + x + (x - 6) = 80
Simplifying the equation:
4x - 6 = 80
4x = 86
x = 21.5
Therefore, the length of the middle-sized piece is 21.5 inches.
The longest piece is 2 * 21.5 = 43 inches.
The shortest piece is 21.5 - 6 = 15.5 inches.
Middle-sized piece = x
Shortest piece = x - 6
The equation for the sum of the three pieces is:
2x + x + (x - 6) = 80
Simplifying the equation:
4x - 6 = 80
4x = 86
x = 21.5
Therefore, the length of the middle-sized piece is 21.5 inches.
The longest piece is 2 * 21.5 = 43 inches.
The shortest piece is 21.5 - 6 = 15.5 inches.
Related Questions
a carpenter needs 6 pieces of wood 3 1/2 feet long. the carpenter has two 10 foot boards. does the c...
A carpenter sawed a piece of wood into 3 pieces of wood into 3 pieces. The ratio of wood pieces is 1...
A carpenter needs 5 pieces of wood, each 4 feet long. If he can only buy 8-foot long pieces of wood,...
Select the correct answer from each drop-down menu.
A carpenter is building a triangular frame. S...