Question

find the standard form of the equation of the ellipse with center (0,0) and foci at (+- 4square root 3, 0) and verticies (+-8,0)

x^2/a^2 + =y^2/b^2 = 1

a = 8

b = sqrt(8^2 - (4sqrt3)^2)
..= sqrt(64 - 48) = sqrt(16) = 4

Thus, x^2/64 + y^2/16 = 1

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