Asked by Kim
A painter needs to cover a triangular region 62 meters by 68 meters by 70 meters. A can of paint covers 70 square meters. How many cans will be needed?
Answers
Answered by
drwls
Let s be half the sum of the three sides (100 m, in this case). If a, b and c are the side lengths of the triangle, the area is
sqrt[s(s-a)(s-b)(s-c)]
= sqrt[100*38*32*30] = 1910 m^2
1910/70 = 27.3 cans are needed
sqrt[s(s-a)(s-b)(s-c)]
= sqrt[100*38*32*30] = 1910 m^2
1910/70 = 27.3 cans are needed
Answered by
Alpha Ihove
Please can you explain this maths question to me regarding trigonometry triangular
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