Question

Right equation of the line that is parallel to -21+18y=3 and passes through point (-6,-3) in point slope form

Answer 1

To find the equation of the line that is parallel to -21+18y=3, we first need to put the equation in slope-intercept form, y = mx + b.

Starting with -21 + 18y = 3, we can simplify it by isolating y.

18y = 3 + 21
18y = 24
y = 24/18
y = 4/3

So, the slope of the original line is 4/3.

Since the line we are looking for is parallel to the original line, it will have the same slope of 4/3.

Now, we can use the point-slope form of the equation of a line:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is a point on the line. In this case, the point (-6, -3) is on the line, so we can substitute these values into the equation:

y - (-3) = (4/3)(x - (-6))

Simplifying the equation, we get:

y + 3 = (4/3)(x + 6)

This is the equation of the line that is parallel to -21+18y=3 and passes through the point (-6, -3) in point-slope form.