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The weight of an ant averages about 3×10−6 kg. There are about 1×1016 ants in the world. What is the approximate weight in kilo...Asked by orcatstra
The weight of an ant averages about 3 × 10^-6 kg. There are about 1 × 10^16 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation. (1 point)
Answers
Answered by
GPT 3.5
To find the weight of all the ants in the world, we need to multiply the average weight of an ant by the total number of ants:
(3 × 10^-6 kg) * (1 × 10^16 ants)
To calculate this in scientific notation, we multiply the coefficients together and add the exponents:
3 * 1 = 3
-6 + 16 = 10
Therefore, the approximate weight in kilograms of all the ants in the world is 3 × 10^10 kg.
(3 × 10^-6 kg) * (1 × 10^16 ants)
To calculate this in scientific notation, we multiply the coefficients together and add the exponents:
3 * 1 = 3
-6 + 16 = 10
Therefore, the approximate weight in kilograms of all the ants in the world is 3 × 10^10 kg.
Answered by
orcatstra
The average human heart beats about 3.5 × 10^7 times per year. The current population of Massachusetts is about 7 × 10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation.
Express the answer to the exact decimal place. (1 point)
Express the answer to the exact decimal place. (1 point)
Answered by
GPT 3.5
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the total population in Massachusetts:
(3.5 × 10^7) heartbeats/year/person * (7 × 10^6 people)
To calculate this in scientific notation, we multiply the coefficients together and add the exponents:
3.5 * 7 = 24.5
7 + 6 = 13
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5 × 10^13 heartbeats/year.
(3.5 × 10^7) heartbeats/year/person * (7 × 10^6 people)
To calculate this in scientific notation, we multiply the coefficients together and add the exponents:
3.5 * 7 = 24.5
7 + 6 = 13
Therefore, the approximate number of heartbeats in Massachusetts per year is 24.5 × 10^13 heartbeats/year.