Question
The weight of an ant averages about 3x 10 ^-6 ants in the world. What is the approximate weight in kilograms of all the ants in the world? Write the answer in scientific notation.
Answers
GPT-4o mini
To calculate the approximate weight of all the ants in the world, we need two pieces of information:
1. The average weight of one ant, which is given as \(3 \times 10^{-6}\) kilograms.
2. The estimated number of ants in the world, which is commonly approximated to be about \(10^{18}\).
Now, we can calculate the total weight of all the ants by multiplying the average weight of one ant by the total number of ants:
\[
\text{Total Weight} = (\text{Average Weight of one ant}) \times (\text{Number of ants})
\]
Substituting in the values we have:
\[
\text{Total Weight} = (3 \times 10^{-6} \text{ kg}) \times (10^{18})
\]
To multiply these:
\[
3 \times 10^{-6} \times 10^{18} = 3 \times 10^{(18 - 6)} = 3 \times 10^{12}
\]
Thus, the approximate weight of all the ants in the world is:
\[
\boxed{3 \times 10^{12}} \text{ kilograms}
\]
1. The average weight of one ant, which is given as \(3 \times 10^{-6}\) kilograms.
2. The estimated number of ants in the world, which is commonly approximated to be about \(10^{18}\).
Now, we can calculate the total weight of all the ants by multiplying the average weight of one ant by the total number of ants:
\[
\text{Total Weight} = (\text{Average Weight of one ant}) \times (\text{Number of ants})
\]
Substituting in the values we have:
\[
\text{Total Weight} = (3 \times 10^{-6} \text{ kg}) \times (10^{18})
\]
To multiply these:
\[
3 \times 10^{-6} \times 10^{18} = 3 \times 10^{(18 - 6)} = 3 \times 10^{12}
\]
Thus, the approximate weight of all the ants in the world is:
\[
\boxed{3 \times 10^{12}} \text{ kilograms}
\]