Asked by Sandy
A hollow tube (I = MR2) rolls without slipping along the surface. The ratio of its translational kinetic energy to its rotational kinetic energy is
a. 1
b. 2
c. 3
d. 1/2
e. 1/3
I say A becasue both add up to get the total kinetic energy.
a. 1
b. 2
c. 3
d. 1/2
e. 1/3
I say A becasue both add up to get the total kinetic energy.
Answers
Answered by
drwls
Translational KE is (1/2) M V^2
Rotational KE is (1/2)I w^2
= (1/2) M R^2*(V/R)^2 = (1/2) M V^2
Your answer is correct but your reasoning is faulty. The ratio could be anything and they would still add up to give total KE
Rotational KE is (1/2)I w^2
= (1/2) M R^2*(V/R)^2 = (1/2) M V^2
Your answer is correct but your reasoning is faulty. The ratio could be anything and they would still add up to give total KE
Answered by
First Name
The Answer is "I don't know. Ask I".
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