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An electron is accelerated through a uniform electric field of magnitude 2.5x10^2 N/C with an initial speed of 1.2x10^6 m/s par...Asked by Linn
An electron is accelerated through a uniform electric field of magnitude 2.5x10^2 N/C with an initial speed of 1.2x10^6 m/s parallel to the electric field.
a) Calculate the work done on the electron by the field when the electron has travelled 2.5 cm in the field.
b) Calculate the speed of the electron after it has travelled 2.5 cm in the field.
c) If the direction of the electric field is reversed, how far will the electron move into the field before coming to rest?
a) Calculate the work done on the electron by the field when the electron has travelled 2.5 cm in the field.
b) Calculate the speed of the electron after it has travelled 2.5 cm in the field.
c) If the direction of the electric field is reversed, how far will the electron move into the field before coming to rest?
Answers
Answered by
drwls
a) e E x
b) Assume the work done (above) equals the increase in kinetic energy
c) It will travel until
E e x = intial kinetic energy
b) Assume the work done (above) equals the increase in kinetic energy
c) It will travel until
E e x = intial kinetic energy
Answered by
Linn
Should the answer for B be 1.5x10^6 m/s because my book says it's wrong...
Answered by
Linn
Oh, and what do you mean by 'x'?
Answered by
Linn
Also, is there a final kinetic energy? I'm just really confused by this...
Answered by
Linn
Won't the kinetic energies for question b and c be the same?
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