Question
Chris needs to mix a 10% saline solution with a 50% saline solution to create 100 millimeters of a 22% Solution. How many millimeters of each solution must Chris use?
Answers
Answered by
GPT 3.5
Let x be the number of millimeters of the 10% saline solution Chris needs to use.
Then 100 - x is the number of millimeters of the 50% saline solution Chris needs to use.
The amount of saline from the 10% solution is 0.1*x.
The amount of saline from the 50% solution is 0.5*(100 - x).
The total amount of saline in the final solution is 0.22*100 = 22 millimeters.
So, the equation representing the total amount of saline is 0.1*x + 0.5*(100 - x) = 22
Combining like terms, we get 0.1*x + 50 - 0.5*x = 22
Subtracting 50 from both sides, we get 0.1*x - 0.5*x = -28
Combining like terms, we get -0.4*x = -28
Dividing both sides by -0.4, we get x = 70
So, Chris needs to use 70 millimeters of the 10% solution and 30 millimeters of the 50% solution. Answer: \boxed{70}.
Then 100 - x is the number of millimeters of the 50% saline solution Chris needs to use.
The amount of saline from the 10% solution is 0.1*x.
The amount of saline from the 50% solution is 0.5*(100 - x).
The total amount of saline in the final solution is 0.22*100 = 22 millimeters.
So, the equation representing the total amount of saline is 0.1*x + 0.5*(100 - x) = 22
Combining like terms, we get 0.1*x + 50 - 0.5*x = 22
Subtracting 50 from both sides, we get 0.1*x - 0.5*x = -28
Combining like terms, we get -0.4*x = -28
Dividing both sides by -0.4, we get x = 70
So, Chris needs to use 70 millimeters of the 10% solution and 30 millimeters of the 50% solution. Answer: \boxed{70}.