N=5
l = from zero, in integers, to n-1.
msubl = -ell to + ell.
msubs = +1/2 and -1/2 for each ell listed.
So the total number of orbitals with n=5 will be 2*number of ell values.
What is the total number of orbitals associated with the principal quantum number n = 5?
2 answers
25