Determine the distance between −18.26 and −2.45 on a number line.(1 point)
Responses
20.71
20.71
−20.71
negative 20.71
−15.81
negative 15.81
15.81
17 answers
The correct answer is 15.81.
Subtract 24−(−15).(1 point)
The result of the subtraction 24 - (-15) is 39.
What is 17 4/9 + 5/9 − 8 − 10?(1 point)
Responses
−7
negative 7
20
20
−1
negative 1
0
Responses
−7
negative 7
20
20
−1
negative 1
0
To solve the expression 17 4/9 + 5/9 - 8 - 10, we first add the fractions 4/9 and 5/9, which gives us 9/9 or simply 1.
Then we can rewrite the expression as 17 + 1 - 8 - 10.
Next, we can add 17 and 1, which gives us 18.
Finally, we can subtract 8 and 10 from 18 to get 0.
Therefore, the answer is 0.
Then we can rewrite the expression as 17 + 1 - 8 - 10.
Next, we can add 17 and 1, which gives us 18.
Finally, we can subtract 8 and 10 from 18 to get 0.
Therefore, the answer is 0.
Which context describes a difference of rational numbers?(1 point)
Responses
The team’s score did not change during the game.
The team’s score did not change during the game.
The team’s score increased when scoring.
The team’s score increased when scoring.
A football player loses yards on a play.
A football player loses yards on a play.
A football player gains yards on a play.
Responses
The team’s score did not change during the game.
The team’s score did not change during the game.
The team’s score increased when scoring.
The team’s score increased when scoring.
A football player loses yards on a play.
A football player loses yards on a play.
A football player gains yards on a play.
A football player gains yards on a play describes a difference of rational numbers.
Joey walked east for 15 2/3 meters from home. Then, he walked west for 21 34 meters. How far was Joey from home?(1 point)/
Joey was
meters from home.
Joey was
meters from home.
To find out how far Joey was from home, we need to find the difference between the distance he walked east and the distance he walked west.
The distance Joey walked east is 15 2/3 meters.
The distance Joey walked west is 21 34 meters.
We can subtract these distances to find how far Joey was from home:
15 2/3 - 21 34
To subtract mixed numbers, we need to convert them into improper fractions.
15 2/3 = (3 * 15 + 2) / 3 = 47/3
21 34/1 = (1 * 21 + 34) / 1 = 55/1
Now, we can subtract:
47/3 - 55/1
To subtract fractions, we need to have a common denominator. The least common multiple of 3 and 1 is 3.
47/3 - 55/1 = (47*1)/(3*1) - (55*3)/(1*3) = 47/3 - 165/3 = (47 - 165)/3 = -118/3
So, Joey was -118/3 meters from home.
The distance Joey walked east is 15 2/3 meters.
The distance Joey walked west is 21 34 meters.
We can subtract these distances to find how far Joey was from home:
15 2/3 - 21 34
To subtract mixed numbers, we need to convert them into improper fractions.
15 2/3 = (3 * 15 + 2) / 3 = 47/3
21 34/1 = (1 * 21 + 34) / 1 = 55/1
Now, we can subtract:
47/3 - 55/1
To subtract fractions, we need to have a common denominator. The least common multiple of 3 and 1 is 3.
47/3 - 55/1 = (47*1)/(3*1) - (55*3)/(1*3) = 47/3 - 165/3 = (47 - 165)/3 = -118/3
So, Joey was -118/3 meters from home.
Joey walked east for 15 2/3 meters from home. Then, he walked west for 21 3/4 meters. How far was Joey from home?(1 point)
Joey was
meters from home.
Joey was
meters from home.
To find out how far Joey was from home, we need to find the difference between the distance he walked east and the distance he walked west.
The distance Joey walked east is 15 2/3 meters.
The distance Joey walked west is 21 3/4 meters.
To make the subtraction easier, let's convert both mixed numbers into improper fractions.
15 2/3 = (3 * 15 + 2) / 3 = 47/3
21 3/4 = (4 * 21 + 3) / 4 = 87/4
Now we can subtract these distances:
47/3 - 87/4
To subtract fractions, we need a common denominator, which in this case is 12.
Multiplying the numerator and denominator of the first fraction by 4:
(47 * 4) / (3 * 4) = 188/12
Multiplying the numerator and denominator of the second fraction by 3:
(87 * 3) / (4 * 3) = 261/12
Now we can subtract the fractions:
188/12 - 261/12 = (188 - 261)/12 = -73/12
So, Joey was -73/12 meters from home.
The distance Joey walked east is 15 2/3 meters.
The distance Joey walked west is 21 3/4 meters.
To make the subtraction easier, let's convert both mixed numbers into improper fractions.
15 2/3 = (3 * 15 + 2) / 3 = 47/3
21 3/4 = (4 * 21 + 3) / 4 = 87/4
Now we can subtract these distances:
47/3 - 87/4
To subtract fractions, we need a common denominator, which in this case is 12.
Multiplying the numerator and denominator of the first fraction by 4:
(47 * 4) / (3 * 4) = 188/12
Multiplying the numerator and denominator of the second fraction by 3:
(87 * 3) / (4 * 3) = 261/12
Now we can subtract the fractions:
188/12 - 261/12 = (188 - 261)/12 = -73/12
So, Joey was -73/12 meters from home.
simplafie pls
To simplify -73/12, we can find the greatest common divisor (GCD) of the numerator and denominator and divide both by it.
The GCD of 73 and 12 is 1, so we can simplify the fraction by dividing both the numerator and denominator by 1:
(-73/1) / (12/1) = -73/12
Therefore, the simplified form of -73/12 is -73/12.
The GCD of 73 and 12 is 1, so we can simplify the fraction by dividing both the numerator and denominator by 1:
(-73/1) / (12/1) = -73/12
Therefore, the simplified form of -73/12 is -73/12.
Which situation describes opposite quantities that when combined would equal 0?(1 point)
Responses
A plane ascends to 15,000 feet and then descends 10,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then descends 10,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 10,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 10,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then descends 15,000 feet. How many feet above the ground is the plane?
Responses
A plane ascends to 15,000 feet and then descends 10,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then descends 10,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 10,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 10,000 feet and then ascends 15,000 feet. How many feet above the ground is the plane?
A plane ascends to 15,000 feet and then descends 15,000 feet. How many feet above the ground is the plane?
The situation that describes opposite quantities that, when combined, would equal 0 is:
"A plane ascends to 15,000 feet and then descends 15,000 feet. How many feet above the ground is the plane?"
"A plane ascends to 15,000 feet and then descends 15,000 feet. How many feet above the ground is the plane?"
Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.(4 points)
To find the change in temperature during the three hours, we subtract the initial temperature from the final temperature.
Initial temperature: -5.8 degrees Celsius
Final temperature: -1.6 degrees Celsius
Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
Therefore, the change in temperature during the three hours is 4.2 degrees Celsius.
The positive value of the change (+4.2) indicates an increase in temperature over the three hours. This means that the temperature rose by 4.2 degrees Celsius from 9 a.m. to noon.
Initial temperature: -5.8 degrees Celsius
Final temperature: -1.6 degrees Celsius
Change in temperature = Final temperature - Initial temperature
Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius
Therefore, the change in temperature during the three hours is 4.2 degrees Celsius.
The positive value of the change (+4.2) indicates an increase in temperature over the three hours. This means that the temperature rose by 4.2 degrees Celsius from 9 a.m. to noon.