Asked by Bobbie
determine the distance from earths centre where the force of gravity acting on a space probe is only 11% of the force acting on the same probe at earths surface. Express your answer in terms of earths radius, rE
Answers
Answered by
bobpursley
Force is inversely prop to distance squared, so...
.11=1/(distance/rE)^2
.11=1/(distance/rE)^2
Answered by
Damon
F = G Me m/R^2
Fe= G Me m/Re^2
F/Fe = 11/100 = 1/R^2 / 1/Re^2 = Re^2/R^2
11/100 = Re^2/R^2
R/Re = sqrt(100/11) = 10/sqrt 11
= 3.01
so
R = 3.01 Re
Fe= G Me m/Re^2
F/Fe = 11/100 = 1/R^2 / 1/Re^2 = Re^2/R^2
11/100 = Re^2/R^2
R/Re = sqrt(100/11) = 10/sqrt 11
= 3.01
so
R = 3.01 Re
Answered by
drwls
The force of gravity is proportional to 1/r^2, where r is measured from the center of the earth. Therefore
(r/rE)^-2 = 0.11
r/rE = sqrt (1/0.11) = sqrt 9.09 = 3.015
(r/rE)^-2 = 0.11
r/rE = sqrt (1/0.11) = sqrt 9.09 = 3.015
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