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Asked by eve

A solution was prepared by dissolving 0.163 g of sugar, (C12H22O11 MW = 3423gmol)
in 100.00 mL water. What is the molarity of this solution?
16 years ago

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Answered by drwls
You left out a decimal in the MW. It is 342.3 g/mol. 0.163 g is therefore 0.000475 moles. Divide that by 0.100 L to get the molarity (M)in moles/Liter
16 years ago

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