Question

A solution was prepared by dissolving 18.00 grams glucose in 150.0 grams water. The resulting solution was found to have a boiling point of 100.34 0C. Calculate the molar mass of glucose. (Kb (water) = 0.51 0C kg/mol; Tb(water) = 80. 0 0C)

Answer 1

I'm not sure what you mean for Tb = 80. If you mean boiling point for H2O that is 100 C and that's the number I will use.
delta T = Kb*molality
100.34-100 = 0.34 =*0.51 molality.
Solve for molality = mols/Kg solvent.
You know m and you know kg solvent is 0.150. Solve for mols.
Then mols = grams/molar mass. You know mols and grams, solve for molar mass = ?
Post your work if you get stuck. I ran through the calculations in my head and got about 180 g/mol.

Answer 2

Nothing

Answer 3

yes