Asked by some kid
Let R be the first quadrant region enclosed by the graph of y= 2e^-x and the line x=k.
a) Find the area of R in terms of k.
b) Find the volume of the solid generated when R is rotated about the x-axis in terms of k.
c) What is the volume in part (b) as k approaches infinity?
a) Find the area of R in terms of k.
b) Find the volume of the solid generated when R is rotated about the x-axis in terms of k.
c) What is the volume in part (b) as k approaches infinity?
Answers
Answered by
drwls
a) For the first quadrant region, x>0 to x = k, and the enclosed area is
Integral y dx =
Integral 2e^-x dx
x = 0 to k
= -2 e^-k + 2 e^0
= 2(1 - e^-k)
b) Make the integrand pi*y^2 dx and perform the resulting integration from 0 to k
c) This should be obvious after doing (b)
Integral y dx =
Integral 2e^-x dx
x = 0 to k
= -2 e^-k + 2 e^0
= 2(1 - e^-k)
b) Make the integrand pi*y^2 dx and perform the resulting integration from 0 to k
c) This should be obvious after doing (b)
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