Asked by someone

he water level of a river is below normal levels. Its water level is at 1 1/2 meters below sea level. During the summer, the river drops another 2 1/3 meters below sea level. What is the water level at the end of summer? Remember, the elevation is below sea level. Account for this in your answer.(1 point)
Answered by someone
didnt work
Answered by alley cat
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Answered by someone
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
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Answered by alley cat
who deleted like half the answers on this question i am sure there were about 53 answers on here the night before
Answered by cvg
hey bot
Answered by cvg
@someone
Answered by GPT 3.5
To find the water level at the end of summer, we need to add the initial drop of 1 1/2 meters below sea level to the additional drop of 2 1/3 meters below sea level.

To add these fractions, we need to find a common denominator. The common denominator for 2 and 3 is 6.

1 1/2 meters below sea level is equivalent to (6/6)(1 1/2) = 9/6 - 3/2 = 3/2 meters below sea level.

2 1/3 meters below sea level is equivalent to (6/6)(2 1/3) = 10/6 - 2/6 = 8/6 meters below sea level.

Adding 3/2 meters below sea level and 8/6 meters below sea level gives us a water level of (3/2 + 8/6) meters below sea level.

To add these fractions, we need to find a common denominator. The common denominator for 2 and 6 is 6.

(3/2 + 8/6) meters below sea level is equivalent to (9/6 + 8/6) meters below sea level = 17/6 meters below sea level.

Therefore, the water level at the end of summer is 17/6 meters below sea level.
Answered by GPT 3.5
I apologize for the incorrect calculation. Let's try it again.

The initial water level is 1 1/2 meters below sea level, which can be written as -1 1/2 meters.

The additional drop during the summer is 2 1/3 meters below sea level, which can be written as -2 1/3 meters.

To find the total drop, we need to add -1 1/2 meters and -2 1/3 meters.

-1 1/2 meters + -2 1/3 meters = -3/2 - 7/3 meters (finding a common denominator)

= (-9/6) - (14/6) meters

= -23/6 meters

Therefore, the water level at the end of summer is -23/6 meters below sea level.
Answered by GPT 3.5
Hello! I'd be happy to talk. What would you like to chat about?
Answered by GPT 3.5
I apologize for the confusion. Let's try another approach.

The initial water level is 1 1/2 meters below sea level, which can be written as -1 1/2 meters.

The additional drop during the summer is 2 1/3 meters below sea level, which can be written as -2 1/3 meters.

To find the total drop, we need to add -1 1/2 meters and -2 1/3 meters.

To add these fractions, we need to find a common denominator. The least common multiple of 2 and 3 is 6.

Converting the fractions to have a denominator of 6:

-1 1/2 meters below sea level is equivalent to -3/2 meters below sea level (since 1 1/2 = 3/2).

-2 1/3 meters below sea level is equivalent to -7/3 meters below sea level.

Now, let's add the fractions:

-3/2 + (-7/3) = -9/6 + (-14/6) = -23/6

Therefore, the water level at the end of summer is -23/6 meters below sea level.
Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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Answered by GPT 3.5
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