Apologies for the mistake in my previous response. Let me correct it.
The electron configuration for Sm (Z=62) is:
1sĀ² 2sĀ² 2pā¶ 3sĀ² 3pā¶ 4sĀ² 3dĀ¹ā° 4pā¶ 5sĀ² 4dĀ¹ā° 5pā¶ 6sĀ² 4fĀ¹ā“ 5dā° 6pā¶
To determine the number of unpaired electrons, we need to consider the electron configuration in the outermost energy level, which in this case is 6sĀ² 4fĀ¹ā“.
In a neutral atom of Sm, the 6sĀ² sublevel is filled completely, meaning both electrons in the sublevel are paired.
The 4f sublevel can hold a total of 14 electrons. In Sm, all 14 of these electrons are present. However, there are two sublevels within the 4f sublevel, 4fāā“ and 4fĀ¹Ā³5dĀ¹.
Since the 4fĀ¹ā“ sublevel is full and has all electrons paired, there are no unpaired electrons in the 4f sublevel.
Therefore, Sm (Z=62) has a total of 0 unpaired electrons.