The element with atomic number Z=62 is samarium (Sm).
To determine the number of unpaired electrons, we need to find the electron configuration of neutral samarium (Sm):
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f6
The valence shell for samarium is the 6s shell, and it contains 2 electrons. All the other shells are filled. So, there are two unpaired electrons in samarium.
To write the electron configuration of the Sm3+ ion, we need to remove 3 electrons from the neutral configuration to match the 3+ charge.
The electron configuration of Sm3+ ion is:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f5
how Sm many upaired electrons are in (Z=62) and write the electron configuration of Sm3+ ion.
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