a. The number of "x" lengths of fencing that will be used is 4. This is because there are 4 sides, and each side has a width of x.
So the total length of the sides with width x is 4x.
This leaves 800 - 4x meters of fencing for the two long sides.
Each long side will have half of the remaining fence length, so each one will have (800 - 4x)/2 = 400 - 2x meters of fence.
b. The equation that represents the area of the field is:
Area = length x width
Substituting x for the width and the answer from part a) for the length, the equation becomes:
Area = (400 - 2x) * x
c. To find the maximum area, we need to find the vertex of the quadratic function. The vertex can be found using the formula:
x = -b / 2a
In this case, a = -2 and b = 400.
x = -400 / (2 * -2) = -400 / -4 = 100
Substituting x = 100 back into the equation for the area, we get:
Area = (400 - 2*100) * 100
= 200 * 100
= 20000
So the maximum area of the field is 20000 square meters.
d. Each third of the playing field will have the same width, which is x.
The length of each third can be found by dividing the total length (400 - 2x) by 3. So each third will have a length of (400 - 2x)/3.
A rectangular playing field will be divided by fences as shown here. A total of 800 metres of fence is
available. Since we don’t know the width, we can call it x. (6 marks)
a. How many “x” lengths of fencing will be used? How
much of the 800 metres of fencing will that leave for
the two long sides? How much fence will that leave for
each one of the long sides?
x
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b. Using x as your width and your last answer in a) as your length, write an equation that
represents the area of this field. Remember that area of a rectangle = length x width.
c. This equation for the area should be a quadratic function. Find the maximum area.
d. What are the dimensions—length and width—for each third of this playing field?
5 answers
n 1 hour, Nate paddles his canoe 6 km upstream and then returns back downstream to the dock. The
current in the river is 3 km/h.
a) Create a simplified quadratic equation to model the situation. (3 marks)
b) What is Nate’s speed in still water?
current in the river is 3 km/h.
a) Create a simplified quadratic equation to model the situation. (3 marks)
b) What is Nate’s speed in still water?
a) To create a simplified quadratic equation to model the situation, we can use the formula:
Time = Distance / Speed
The time taken to paddle upstream is given as 1 hour, so we can set up the equation:
1 = 6 / (Nate's speed - 3)
The time taken to paddle downstream is also given as 1 hour, so we can set up the equation:
1 = 6 / (Nate's speed + 3)
To simplify this, we can cross-multiply:
Nate's speed - 3 = 6 / 1
Nate's speed + 3 = 6 / 1
Simplifying further, we get:
Nate's speed - 3 = 6
Nate's speed + 3 = 6
b) To find Nate's speed in still water, we can solve the two equations simultaneously.
Solving the first equation:
Nate's speed - 3 = 6
Nate's speed = 6 + 3
Nate's speed = 9 km/h
Solving the second equation:
Nate's speed + 3 = 6
Nate's speed = 6 - 3
Nate's speed = 3 km/h
Since Nate's speed cannot be both 9 km/h and 3 km/h, there seems to be an error in the problem setup or data provided. Please double-check the information given.
Time = Distance / Speed
The time taken to paddle upstream is given as 1 hour, so we can set up the equation:
1 = 6 / (Nate's speed - 3)
The time taken to paddle downstream is also given as 1 hour, so we can set up the equation:
1 = 6 / (Nate's speed + 3)
To simplify this, we can cross-multiply:
Nate's speed - 3 = 6 / 1
Nate's speed + 3 = 6 / 1
Simplifying further, we get:
Nate's speed - 3 = 6
Nate's speed + 3 = 6
b) To find Nate's speed in still water, we can solve the two equations simultaneously.
Solving the first equation:
Nate's speed - 3 = 6
Nate's speed = 6 + 3
Nate's speed = 9 km/h
Solving the second equation:
Nate's speed + 3 = 6
Nate's speed = 6 - 3
Nate's speed = 3 km/h
Since Nate's speed cannot be both 9 km/h and 3 km/h, there seems to be an error in the problem setup or data provided. Please double-check the information given.
What is the initial height of the rocket? (1 mark)
b) What is the maximum height of the rocket? (1 mark)
c) How long after launch does the rocket reach the maximum height? (1 mark)
d) How long does it take for the rocket to reach the ground? (3 marks)
e) State the domain and range for this situation.
b) What is the maximum height of the rocket? (1 mark)
c) How long after launch does the rocket reach the maximum height? (1 mark)
d) How long does it take for the rocket to reach the ground? (3 marks)
e) State the domain and range for this situation.
Unfortunately, the initial height of the rocket, as well as the equation or information needed to calculate it, is not mentioned in the given question. Therefore, it is not possible to determine the initial height of the rocket.
Similarly, without the equation or information regarding the rocket's flight path, it is not possible to determine the maximum height of the rocket, the time it takes to reach the maximum height, or the time it takes to reach the ground. These values would depend on the specific data provided in the question.
The domain and range for this situation would also depend on the specific data and context given in the question. Without that information, it is not possible to accurately state the domain (possible inputs) and range (possible outputs) for the situation.
Similarly, without the equation or information regarding the rocket's flight path, it is not possible to determine the maximum height of the rocket, the time it takes to reach the maximum height, or the time it takes to reach the ground. These values would depend on the specific data provided in the question.
The domain and range for this situation would also depend on the specific data and context given in the question. Without that information, it is not possible to accurately state the domain (possible inputs) and range (possible outputs) for the situation.