Question
Solve Log(x^2 + 4) = 2 + log x -log 20
Answers
Answered by
oobleck
log(x^2 + 4) = 2 + log x - log 20
x^2+4 = 100 * x / 20
x^2 + 4 = 5x
x^2-5x+4 = 0
(x-1)(x-4) = 0
x = 1 or 4
x^2+4 = 100 * x / 20
x^2 + 4 = 5x
x^2-5x+4 = 0
(x-1)(x-4) = 0
x = 1 or 4
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