Question

Calculate the relative molecular mass of
NaNO3

Answer 1

To calculate the relative molecular mass of NaNO3, we need to find the sum of the atomic masses of its constituent atoms.

The atomic mass of Na (Sodium) is 22.99 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.

Since there is 1 Na, 1 N, and 3 O atoms in NaNO3, we can calculate the relative molecular mass as follows:
(1 x 22.99) + (1 x 14.01) + (3 x 16.00) = 22.99 + 14.01 + 48.00 = 85.00 g/mol

Therefore, the relative molecular mass of NaNO3 is 85.00 g/mol.

Answer 2

Calculate the relative molecular mass of CuSO4.5H20

Answer 3

To calculate the relative molecular mass of CuSO4·5H2O, we need to find the sum of the atomic masses of all its constituent atoms.

The atomic mass of Cu (Copper) is 63.55 g/mol.
The atomic mass of S (Sulfur) is 32.06 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.
The atomic mass of H (Hydrogen) is 1.01 g/mol.

Since there is 1 Cu, 1 S, 4 O, 10 H, and 2 O atoms in CuSO4·5H2O, we can calculate the relative molecular mass as follows:
(1 x 63.55) + (1 x 32.06) + (4 x 16.00) + (10 x 1.01) + (2 x 16.00) = 63.55 + 32.06 + 64.00 + 10.10 + 32.00 = 201.71 g/mol

Therefore, the relative molecular mass of CuSO4·5H2O is 201.71 g/mol.

Answer 4

Calculate the relative molecular mass of Pb(NO3)2

Answer 5

To calculate the relative molecular mass of Pb(NO3)2, we need to find the sum of the atomic masses of all its constituent atoms.

The atomic mass of Pb (Lead) is 207.2 g/mol.
The atomic mass of N (Nitrogen) is 14.01 g/mol.
The atomic mass of O (Oxygen) is 16.00 g/mol.

Since there is 1 Pb, 2 N, and 6 O atoms in Pb(NO3)2, we can calculate the relative molecular mass as follows:
(1 x 207.2) + (2 x 14.01) + (6 x 16.00) = 207.2 + 28.02 + 96.00 = 331.22 g/mol.

Therefore, the relative molecular mass of Pb(NO3)2 is 331.22 g/mol.