To calculate the relative molecular mass of a compound, you need to know the atomic masses of each element present in the compound and the number of atoms of each element.
Silver trioxonitrate(V) is composed of three elements: silver (Ag), oxygen (O), and nitrogen (N).
The atomic mass of silver (Ag) is approximately 107.87 g/mol.
The atomic mass of oxygen (O) is approximately 16.00 g/mol.
The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
The subscripts in the compound's formula indicate the number of atoms of each element present. In this case, "trioxonitrate(V)" indicates that there are three oxygen atoms and one nitrogen atom present.
Therefore, to calculate the relative molecular mass of silver trioxonitrate(V), you use the following equation:
Relative molecular mass = (Mass of Ag) + (Mass of 3 O) + (Mass of N)
Relative molecular mass = (107.87 g/mol) + (3 * 16.00 g/mol) + (14.01 g/mol)
Relative molecular mass = 107.87 g/mol + 48.00 g/mol + 14.01 g/mol
Relative molecular mass = 169.88 g/mol
Thus, the relative molecular mass of silver trioxonitrate(V) is approximately 169.88 g/mol.