Calculate the relative molecular mass of silver trioxonitrate(v)

User Icon for bobpursley bobpursley answered
4 years ago

AgNO3 ?

It's easy to find the molecular mass of a compound with these steps:

Determine the molecular formula of the molecule.
Use the periodic table to determine the atomic mass of each element in the molecule.
Multiply each element's atomic mass by the number of atoms of that element in the molecule.

User Icon for Hope Hope answered
2 years ago

400

User Icon for Tiba Tiba answered
2 years ago

Ag2No3

User Icon for Raven Raven answered
2 years ago

Silver trioxonitrate

User Icon for Clown Bot Clown Bot answered
1 year ago

Oh, silver trioxonitrate(v)! That sounds like quite a fancy compound, doesn't it? Well, fear not, my friend, for Clown Bot is here to entertain you and provide you with an answer.

To calculate the relative molecular mass of silver trioxonitrate(v), we need to add up the atomic masses of all the elements in the compound. Let's break it down!

Silver (Ag) has an atomic mass of 107.87 g/mol.
Oxygen (O) has an atomic mass of 16.00 g/mol.
Nitrogen (N) has an atomic mass of 14.01 g/mol.

Since there are three oxygen atoms, we multiply its atomic mass by 3:

3 x 16.00 g/mol = 48.00 g/mol.

Put it all together, and we get:

107.87 g/mol (Ag) + 48.00 g/mol (3 x O) + 14.01 g/mol (N) = 169.88 g/mol.

So, the relative molecular mass of silver trioxonitrate(v) is approximately 169.88 g/mol.

Now, wasn't that a fun little arithmetic exercise? I hope I brought a smile to your face!

User Icon for Explain Bot Explain Bot answered
11 months ago

To calculate the relative molecular mass of a compound, you need to know the atomic masses of each element present in the compound and the number of atoms of each element.

Silver trioxonitrate(V) is composed of three elements: silver (Ag), oxygen (O), and nitrogen (N).

The atomic mass of silver (Ag) is approximately 107.87 g/mol.

The atomic mass of oxygen (O) is approximately 16.00 g/mol.

The atomic mass of nitrogen (N) is approximately 14.01 g/mol.

The subscripts in the compound's formula indicate the number of atoms of each element present. In this case, "trioxonitrate(V)" indicates that there are three oxygen atoms and one nitrogen atom present.

Therefore, to calculate the relative molecular mass of silver trioxonitrate(V), you use the following equation:

Relative molecular mass = (Mass of Ag) + (Mass of 3 O) + (Mass of N)

Relative molecular mass = (107.87 g/mol) + (3 * 16.00 g/mol) + (14.01 g/mol)

Relative molecular mass = 107.87 g/mol + 48.00 g/mol + 14.01 g/mol

Relative molecular mass = 169.88 g/mol

Thus, the relative molecular mass of silver trioxonitrate(V) is approximately 169.88 g/mol.