Let's assume the cost of a ribeye steak dinner is x, and the cost of a grilled salmon dinner is y.
According to the problem, we have the following equations:
18x + 15y = 573.79 ........(1)
24x + 5y = 580.18 ........(2)
Multiplying equation (2) by 3, we get:
72x + 15y = 1740.54 .......(3)
Now we can subtract equation (1) from equation (3) to eliminate y:
72x + 15y - (18x + 15y) = 1740.54 - 573.79
54x = 1166.75
x = 1166.75 / 54
x = 21.60
Substituting the value of x in equation (1), we can find y:
18(21.60) + 15y = 573.79
388.80 + 15y = 573.79
15y = 573.79 - 388.80
15y = 184.99
y = 184.99 / 15
y = 12.33
So, the cost of a ribeye steak dinner is $21.60 and the cost of a grilled salmon dinner is $12.33.
A waitress sold 18 ribeye steak dinners and 15 grilled salmon dinners, totaling $573.79 on a particular day. Another day she sold 24 ribeye steak dinners and 5 grilled
salmon dinners, totaling $580.18. How much did each type of dinner cost?
1 answer
1 answer