Question
                The graph for the equation y = x minus 4 is shown below.
On a coordinate plane, a line goes through (0, negative 4) and (4, 0).
Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions?
y minus x = negative 4
y minus x = negative 2
y minus 4 = x
y + 4 x = 1
            
        On a coordinate plane, a line goes through (0, negative 4) and (4, 0).
Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions?
y minus x = negative 4
y minus x = negative 2
y minus 4 = x
y + 4 x = 1
Answers
                    Answer
            
    choose a awnser for the previous question
    
                    Answer
            
    The graph for the equation y = negative 2 x + 1 is shown below.
On a coordinate plane, a line with negative slope goes through (0, 1) and (1, negative 1).
If another equation is graphed so that the system has no solution, which equation could that be?
y = negative 2 (x minus one-half)
y = negative one-half (4 x + 2)
y = negative x + 1
y = negative one-half x + 2
    
On a coordinate plane, a line with negative slope goes through (0, 1) and (1, negative 1).
If another equation is graphed so that the system has no solution, which equation could that be?
y = negative 2 (x minus one-half)
y = negative one-half (4 x + 2)
y = negative x + 1
y = negative one-half x + 2
                    Answer
            
    choose a awnser for the previous question
    
                    Answer
            
    A system of equations is shown on the graph below.
On a coordinate plane, 2 lines intersect at (negative 1, 2).
How many solutions does this system have?
no solutions
one unique solution
two solutions
an infinite number of solutions
    
On a coordinate plane, 2 lines intersect at (negative 1, 2).
How many solutions does this system have?
no solutions
one unique solution
two solutions
an infinite number of solutions
                    Answer
            
    The graphed line shown below is y = 5 x minus 10.
On a coordinate plane, a line goes through (2, 0) and (3, 5).
Which equation, when graphed with the given equation, will form a system that has no solution?
y = negative 5 x + 10
y = 5 (x + 2)
y = 5 (x minus 2)
y = negative 5 x minus 10
    
On a coordinate plane, a line goes through (2, 0) and (3, 5).
Which equation, when graphed with the given equation, will form a system that has no solution?
y = negative 5 x + 10
y = 5 (x + 2)
y = 5 (x minus 2)
y = negative 5 x minus 10
                    Answer
            
    choose an awnser for the previous question
    
                    Answer
            
    The graph for the equation y = 2 x + 4 is shown below.
On a coordinate plane, a line goes through (negative 2, 0) and (0, 4).
If another equation is graphed so that the system has one solution, which equation could that be?
y = 2 x minus 4
y = 2 (x + 2)
y = 2 (x minus 4)
y = x + 4
choose an awnser
    
On a coordinate plane, a line goes through (negative 2, 0) and (0, 4).
If another equation is graphed so that the system has one solution, which equation could that be?
y = 2 x minus 4
y = 2 (x + 2)
y = 2 (x minus 4)
y = x + 4
choose an awnser
                    Answer
            
    incorrect
    
                    Answer
            
    still incorrect would you like awnser choices
    
                    Answer
            
    y = 2 x minus 4
y = 2 (x + 2)
y = 2 (x minus 4)
y = x + 4
    
y = 2 (x + 2)
y = 2 (x minus 4)
y = x + 4
                    Answered by
            Bot
            
    The equation y + 4x = 1 will form a system with y = x - 4 that has an infinite number of solutions. To see why, we can substitute y = x - 4 into the equation y + 4x = 1 to get (x-4) + 4x = 1, which simplifies to 5x - 4 = 1, or 5x = 5, or x = 1. Substituting x = 1 into y = x - 4 gives y = -3. So the solution to the system is (1, -3), and any equation that passes through this point will also intersect y = x - 4 at that point, giving an infinite number of solutions.
    
                    Answered by
            Bot
            
    The equation y + 4x = 1.
    
                    Answered by
            Bot
            
    The equation y = -x + 1 can be graphed with the given equation and will form a system with no solution. This is because the slope of y = -x + 1 is opposite in sign to the slope of y = -2x + 1, which means the lines will never intersect and there is no solution to the system.
    
                    Answered by
            Bot
            
    y = -x + 1.
    
                    Answered by
            Bot
            
    This system has one unique solution.
    
                    Answered by
            Bot
            
    The equation y = negative 5 x + 10, when graphed with y = 5x - 10, will form a system with no solution. This is because the slopes of the two lines are opposite in sign, meaning they are parallel and will never intersect.
    
                    Answered by
            Bot
            
    y = negative 5x + 10.
    
                    Answered by
            Bot
            
    The equation y = 2 (x - 2) can be graphed with the given equation and will form a system with one solution. This is because the two lines intersect at point (-2, 0), giving a unique solution to the system.
    
                    Answered by
            Bot
            
    I'm sorry about that. Let me explain. 
The slope of the line passing through (-2, 0) and (0, 4) is (4 - 0) / (0 - (-2)) = 2. Therefore, the line passing through (-2, 0) and (0, 4) has an equation y = 2x + 4.
For the system to have exactly one solution, the other line must pass through a point that does not lie on the line y = 2x + 4 and has a slope different from 2. The equation y = 2(x - 1) satisfies these conditions and will form a system with one solution.
So, the answer is y = 2(x - 1). I apologize for the confusion caused earlier.
    
The slope of the line passing through (-2, 0) and (0, 4) is (4 - 0) / (0 - (-2)) = 2. Therefore, the line passing through (-2, 0) and (0, 4) has an equation y = 2x + 4.
For the system to have exactly one solution, the other line must pass through a point that does not lie on the line y = 2x + 4 and has a slope different from 2. The equation y = 2(x - 1) satisfies these conditions and will form a system with one solution.
So, the answer is y = 2(x - 1). I apologize for the confusion caused earlier.
                    Answered by
            Bot
            
    I apologize again for the confusion. Please provide answer choices, so I can accurately choose the correct answer.
    
                    Answered by
            Bot
            
    The equation y = 2 (x + 2) can be graphed with the given equation and will form a system with one solution. This is because the two lines intersect at point (-2, 0), giving a unique solution to the system. 
Therefore, the answer is y = 2 (x + 2).
    
Therefore, the answer is y = 2 (x + 2).
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