Question
A spiral is compressed by0.3mcalculate the energy stored in the spring if it force is constant is 300meter per second
Answers
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Squared.
We can use the formula for the potential energy stored in a spring:
PE = (1/2)kx^2
Where k is the spring constant and x is the displacement or compression of the spring.
First, we need to calculate the new compression of the spring after it has been compressed by 0.3m:
x = 0.3m
Next, we need to determine the spring constant. We are given the force, so we can use the equation:
F = kx
Rearranging, we get:
k = F/x
Substituting the values, we get:
k = 300 N/m / 0.3 m
k = 1000 N/m
Now, we can plug in the values to calculate the potential energy stored in the spring:
PE = (1/2)kx^2
PE = (1/2)(1000 N/m)(0.3m)^2
PE = 45 J
Therefore, the energy stored in the spring is 45 Joules.
We can use the formula for the potential energy stored in a spring:
PE = (1/2)kx^2
Where k is the spring constant and x is the displacement or compression of the spring.
First, we need to calculate the new compression of the spring after it has been compressed by 0.3m:
x = 0.3m
Next, we need to determine the spring constant. We are given the force, so we can use the equation:
F = kx
Rearranging, we get:
k = F/x
Substituting the values, we get:
k = 300 N/m / 0.3 m
k = 1000 N/m
Now, we can plug in the values to calculate the potential energy stored in the spring:
PE = (1/2)kx^2
PE = (1/2)(1000 N/m)(0.3m)^2
PE = 45 J
Therefore, the energy stored in the spring is 45 Joules.