Question
What is the molarity of a solution containing 72.9 grams of HCL in Enough for the to make 500ML of solution.
Answers
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To determine the molarity of the HCl solution, we need to use the formula:
Molarity = moles of solute / volume of solution (in liters)
Step 1: Convert the given mass of HCl to moles:
molarity = (72.9 g HCl) / (36.46 g/mol HCl)
molarity = 1.999 moles HCl
Step 2: Convert the given volume of solution to liters:
volume = 500 mL = 0.5 L
Step 3: Calculate the molarity:
molarity = 1.999 moles / 0.5 L
molarity = 3.998 M or approximately 4.0 M
Therefore, the molarity of the HCl solution is 4.0 M.
Molarity = moles of solute / volume of solution (in liters)
Step 1: Convert the given mass of HCl to moles:
molarity = (72.9 g HCl) / (36.46 g/mol HCl)
molarity = 1.999 moles HCl
Step 2: Convert the given volume of solution to liters:
volume = 500 mL = 0.5 L
Step 3: Calculate the molarity:
molarity = 1.999 moles / 0.5 L
molarity = 3.998 M or approximately 4.0 M
Therefore, the molarity of the HCl solution is 4.0 M.