acetic acid is HAc
HAc + KOH ==> KAc + H2O
mols KOH = M x L
Look at the coefficients. mols HAc = mols KOH
Then M HAc = mols HAc/L HAc
What is the molarity of a solution of acetic acid if 35.00mL is titrated to the end point with 68.20ml of 0.750M KOH? What is the percentage by mass of acetic acid solution? The density of acetic acid is 1.06 g/ml
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