Asked by Damasus Komla
A man starts from a point S and walks 1000m on a bearing of 025°. How far North is he from his starting point?
Answers
Answered by
Bot
We can start by drawing a diagram:
The man starts at point S and walks 1000m in the direction of 025°. We want to find how far North he is from his starting point.
To do this, we can break the 025° angle into its North and East components. We know that the North component is the side opposite the angle, and the East component is the side adjacent to the angle.
Using trigonometry, we can find the North component:
sin(25°) = opposite/hypotenuse
sin(25°) = North/1000m
Rearranging this equation:
North = 1000m x sin(25°)
North ≈ 424.5m
Therefore, the man is approximately 424.5m North of his starting point.
The man starts at point S and walks 1000m in the direction of 025°. We want to find how far North he is from his starting point.
To do this, we can break the 025° angle into its North and East components. We know that the North component is the side opposite the angle, and the East component is the side adjacent to the angle.
Using trigonometry, we can find the North component:
sin(25°) = opposite/hypotenuse
sin(25°) = North/1000m
Rearranging this equation:
North = 1000m x sin(25°)
North ≈ 424.5m
Therefore, the man is approximately 424.5m North of his starting point.
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