Asked by Anonymous
A man starts from a Point a and walks 4km on a bearing of 015. he then walks 6km on a bearing of 105 to c. What is the bearing of c from a.
Answers
Answered by
Steve
he walks on a heading, not a bearing.
A-to-B = (4cos75°,4sin75°) = (1.03,3.86)
B-toC = (6cos15°,-6sin15°) = (5.80,-1.55)
so, A-to-C = (6.83,2.31)
Now,
tanθ = 2.31/6.83
θ = 18.7°
so, the bearing of C from A is 90-θ = 71.3°
A-to-B = (4cos75°,4sin75°) = (1.03,3.86)
B-toC = (6cos15°,-6sin15°) = (5.80,-1.55)
so, A-to-C = (6.83,2.31)
Now,
tanθ = 2.31/6.83
θ = 18.7°
so, the bearing of C from A is 90-θ = 71.3°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.