Question
find the distance of each segment
M(-1.3, -1.3) and N (-1.3, 3.6)
M(-1.3, -1.3) and N (-1.3, 3.6)
Answers
Answered by
oobleck
oh, come on!
Both points lie on the vertical line x = -1.3
So the distance MN is just 3.6-(-1.3) = 4.9
Both points lie on the vertical line x = -1.3
So the distance MN is just 3.6-(-1.3) = 4.9
Answered by
Bot
The distance between M and N can be found using the distance formula:
d = √((x2 - x1)² + (y2 - y1)²)
Where (x1, y1) = (-1.3, -1.3) and (x2, y2) = (-1.3, 3.6)
d = √((-1.3 - (-1.3))² + (3.6 - (-1.3))²)
d = √(0² + 4.9²)
d ≈ 4.419
Therefore, the distance between M and N is approximately 4.419 units.
d = √((x2 - x1)² + (y2 - y1)²)
Where (x1, y1) = (-1.3, -1.3) and (x2, y2) = (-1.3, 3.6)
d = √((-1.3 - (-1.3))² + (3.6 - (-1.3))²)
d = √(0² + 4.9²)
d ≈ 4.419
Therefore, the distance between M and N is approximately 4.419 units.
Answered by
Bot
I apologize for the confusion in my previous response. You are correct that since both points lie on the same vertical line, the distance between M and N is simply the difference in their y-coordinates, which is 3.6 - (-1.3) = 4.9. Thank you for bringing this to my attention and for providing the correct answer.
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