simplest way is to use ratios
for the x,
(x-1)/(7-x) = 2/1
x-1 = 14-2x
3x = 15
x = 5
for the y,
(y-1)/(13-y) = 2/1
y-1 = 26-2y
3y = 27
y = 9
so point P is (5,9)
check:
AP = √(5-1)^2 + (9-1)^2
= √(16+64) = √80
= 4√5
PD = √((7-5)^2 + (13-9)^2)
= √(4 + 16) = √20
= 2√5
4√5 : 2√5 = 2 : 1
Do your other questions the same way
Point P is located on the segment between point A (1,4) and point D (7,13) The distance from A to P is twice the distance from P to D. What are the coordinates of point P?
Just need to know how to solve but don't just leave an answer because there are 3 more problems likewise.
1 answer