If the length of the pendulum increases four times the the frequency ius

1 answer

halved.

The frequency of a pendulum is given by the formula:

f = 1/T

where f is the frequency and T is the period. The period of a pendulum is given by the formula:

T = 2π√(l/g)

where l is the length of the pendulum and g is the acceleration due to gravity.

If the length of the pendulum is increased four times, then the period becomes:

T' = 2π√(4l/g) = 4π√(l/g)

The frequency of the pendulum with the increased length is:

f' = 1/T' = 1/(4π√(l/g))

To find the relationship between the frequency of the original pendulum and the frequency of the pendulum with the increased length, we can take the ratio:

f'/f = (1/(4π√(l/g)))/(1/(2π√(l/g))) = 1/2

Therefore, if the length of the pendulum increases four times, the frequency is halved.