Question
The frequency of oscillations of a pendulum varies inversely as the square root of the length of the pendulum. If a pendulum of length 25 feet oscillates with a frequency of 100 swings per minute, what would be the frequency of a pendulum of length 16 feet?
Answers
f = k(1/√l)
given: when l = 25 when f = 100
100 = k(1/√100) ----> k = 1000
so f = 1000(1/√l)
plug in l = 16 to find f
given: when l = 25 when f = 100
100 = k(1/√100) ----> k = 1000
so f = 1000(1/√l)
plug in l = 16 to find f
What is L?
Related Questions
The number of oscillations made by a pendulum in a given time is inversely proportional to the lengt...
The period p of a pendulum, or the time it takes for the pendulum to make one complete swing, varies...
The term of a pendulum varies as the square root of it length if the length of a pendulum which beat...