Let the first term of the AP be 'a' and the common difference be 'd'.
Then, from the given information, we can form the following equations:
a + 13d = 96 (1)
a + 24d = 173 (2)
Subtracting equation (1) from (2), we get:
11d = 77
d = 7
Substituting this value of 'd' in equation (1), we get:
a + 91 = 96
a = 5
Now, we can find the 13th term and 56th term as follows:
13th term = a + 12d = 5 + 12(7) = 89
56th term = a + 55d = 5 + 55(7) = 390
Therefore, the sum of 13th and 56th term is:
89 + 390 = 479. Answer: \boxed{479}.
The 14th term of an AP is 96/while the 25th terms is 173/find the Sum of 13th and 56th term.
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1 answer