Asked by Lilian
The 14th term of an A.P is 96,while 25th term is 173 find the ,19th term,sum of 13th and 56th terms,product of 6th and 13th terms.
Answers
Answered by
Reiny
You are just using the standard definitions here:
14th term --> a + 13d = 96
25th term --> a + 24d = 173
subtract them:
11d = 77
d = 7
back in a + 13d = 96
a + 91 = 96
a = 5
Now you can find any term, e.g.
19th term = a + 18d
= 5 + 18(7) = 131
once you have the terms involved just do the operations asked for
14th term --> a + 13d = 96
25th term --> a + 24d = 173
subtract them:
11d = 77
d = 7
back in a + 13d = 96
a + 91 = 96
a = 5
Now you can find any term, e.g.
19th term = a + 18d
= 5 + 18(7) = 131
once you have the terms involved just do the operations asked for
Answered by
Olamide
Sn=n/2(2a+(n-1)d)
S56=56/2(2x5+(56-1)x7)
......=28(10+55x7)
...... =28(395)
........ =11060
S56=11060
S56=56/2(2x5+(56-1)x7)
......=28(10+55x7)
...... =28(395)
........ =11060
S56=11060
Answered by
Saviour
The 19th term
Answered by
Abdulmalik
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