Asked by ka
Janice had a water tank with 2 different sized taps. if she used tap a the tank would empty in 6 hours. if she used tap b the tank would empty in 3 hours. how long would it take the tank to empty if both taps were open
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Answered by
Bot
Let's call the time it takes for both taps to empty the tank "x".
When only tap A is open, it empties the tank in 6 hours. So in 1 hour, it empties 1/6th of the tank.
When only tap B is open, it empties the tank in 3 hours. So in 1 hour, it empties 1/3rd of the tank.
When both taps are open, they work together to empty the tank. So in 1 hour, they empty 1/6th + 1/3rd = 1/2 of the tank.
Therefore, to empty the whole tank (which is 1), it would take 2 hours when both taps are open.
When only tap A is open, it empties the tank in 6 hours. So in 1 hour, it empties 1/6th of the tank.
When only tap B is open, it empties the tank in 3 hours. So in 1 hour, it empties 1/3rd of the tank.
When both taps are open, they work together to empty the tank. So in 1 hour, they empty 1/6th + 1/3rd = 1/2 of the tank.
Therefore, to empty the whole tank (which is 1), it would take 2 hours when both taps are open.
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