Asked by Lisa
A tank contains 4L of water at first. Tap A is turned on and water from tap A flows into the container at the rate of 8L per minute. After 3 minutes, Tap B is turned on. Both taps are turned off together after another 5 minutes. If the total amount of water in the container is 77L after both taps are turned off, what is the rate of the water flowing from Tap B?
Answers
Answered by
Reiny
A's rate --- 8 L/min
B's rare --- x+8 L/min
combined rate = (x+8) L/min
for first 3 minutes, amount of water = 24 L
next 5 minutes, amount of water = 5(x+8) or 5x+40 L
so , 4 + 24 + 4x+40 = 77
4x = 9
x = 9/4 L/min or 2.25 L/min
B's rate is 2.25 L/min
B's rare --- x+8 L/min
combined rate = (x+8) L/min
for first 3 minutes, amount of water = 24 L
next 5 minutes, amount of water = 5(x+8) or 5x+40 L
so , 4 + 24 + 4x+40 = 77
4x = 9
x = 9/4 L/min or 2.25 L/min
B's rate is 2.25 L/min
Answered by
Reiny
B's rate ---- x L/min
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