As x approaches negative infinity, the value of e^x approaches zero and the value of f(x) approaches zero as well. However, since x cannot be negative infinity and f(x) is increasing for x > 0, the minimum value of f(x) occurs at x = 0. Plugging x = 0 into the function, we get:
f(0) = 3(0)e^0 = 0
Therefore, the minimum value of f(x) is 0.
what is the minimum value of f(x)=3xe^x
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