Question
What mass of sucrose (C12H22O11) is needed to make 0.500 L of a 0.200 M solution?
(grams = M x gfm x M; sucrose = 342 g/mol)
(grams = M x gfm x M; sucrose = 342 g/mol)
Answers
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First, we need to calculate the number of moles of sucrose needed to make the solution:
0.200 moles/L x 0.500 L = 0.100 moles
Next, we can use the formula grams = moles x gfm (molar mass) to calculate the mass of sucrose needed:
grams = 0.100 moles x 342 g/mol = 34.2 g
Therefore, 34.2 grams of sucrose is needed to make 0.500 L of a 0.200 M solution.
0.200 moles/L x 0.500 L = 0.100 moles
Next, we can use the formula grams = moles x gfm (molar mass) to calculate the mass of sucrose needed:
grams = 0.100 moles x 342 g/mol = 34.2 g
Therefore, 34.2 grams of sucrose is needed to make 0.500 L of a 0.200 M solution.