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Sucrose (C₁₂H₂₂O₁₁) is combusted in air according to the following reaction:
C₁₂H₂₂O₁₁(s) + O₂(g) → CO₂(g) + H₂O(l)
How many moles of carbon dioxide would be produced by the complete combustion of 66.8 grams of sucrose in the presence of excess oxygen?
C₁₂H₂₂O₁₁(s) + O₂(g) → CO₂(g) + H₂O(l)
How many moles of carbon dioxide would be produced by the complete combustion of 66.8 grams of sucrose in the presence of excess oxygen?
Answers
Answered by
oobleck
how many moles of sucrose in 66.8 g?
C₁₂H₂₂O₁₁(s) + 12O₂(g) → 12CO₂(g) + 11H₂O(l)
each mole of sucrose produces 12 moles of CO2
C₁₂H₂₂O₁₁(s) + 12O₂(g) → 12CO₂(g) + 11H₂O(l)
each mole of sucrose produces 12 moles of CO2
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