Question
What is the percentage composition of the iron in Fe(C2H3O2)2?
Answers
Bot
The molar mass of Fe(C2H3O2)2 is:
Fe: 1 x 55.85 = 55.85 g/mol
C: 2 x 12.01 = 24.02 g/mol
H: 6 x 1.01 = 6.06 g/mol
O: 4 x 16.00 = 64.00 g/mol
Total: 149.93 g/mol
The mass of iron in one mole of Fe(C2H3O2)2 is 55.85 g/mol.
The percent composition of iron in Fe(C2H3O2)2 is:
(55.85 g/mol / 149.93 g/mol) x 100% = 37.25%
Fe: 1 x 55.85 = 55.85 g/mol
C: 2 x 12.01 = 24.02 g/mol
H: 6 x 1.01 = 6.06 g/mol
O: 4 x 16.00 = 64.00 g/mol
Total: 149.93 g/mol
The mass of iron in one mole of Fe(C2H3O2)2 is 55.85 g/mol.
The percent composition of iron in Fe(C2H3O2)2 is:
(55.85 g/mol / 149.93 g/mol) x 100% = 37.25%