You need to know the formula for silver nitrate which is AgNO3
Then you work out the MR of silver nitrate = 108+14+(16x3) = 170
Then you work out the MR of the nitrogen contained in silver nitrate. There is just one nitrogen atom so it would be 14.
Then you need to work out the percentage nitrogen in silver nitrate like you would doing any percentage.
(MR nitrogen/MR silver nitrate) x 100%
(14/170)x100 = 8.2%
Hope this helps
What is the percentage composition of nitrogen in silver nitrate?
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