Asked by mike
Can someone PLEASE solve these for me
1.4x-12/4x
2.d+7/d^2-49
3.t^2-25/t^2+t-20
4.2x^2+6x+4/4x^2-12x-16
5.6-y/y^2-2y-24
You need to use parentheses to clarify the menaing of those expressions. For example, if you mean
(4x-12)/4x instead of 4x - (12/4x), then the answer is
4(x-3)/x = 4[1 - (3/x)]
Similarly,
(d+7)/(d^2-49)= (d+7)/[(d+7)(d-7)]
= 1/(d-7)
Use similar approach with the others. Dactor the numerators and denominatores, and cancel out common factors.
(4x-12)/4x = 4(x-3)/4x = (x-3)/x
1.4x-12/4x
2.d+7/d^2-49
3.t^2-25/t^2+t-20
4.2x^2+6x+4/4x^2-12x-16
5.6-y/y^2-2y-24
You need to use parentheses to clarify the menaing of those expressions. For example, if you mean
(4x-12)/4x instead of 4x - (12/4x), then the answer is
4(x-3)/x = 4[1 - (3/x)]
Similarly,
(d+7)/(d^2-49)= (d+7)/[(d+7)(d-7)]
= 1/(d-7)
Use similar approach with the others. Dactor the numerators and denominatores, and cancel out common factors.
(4x-12)/4x = 4(x-3)/4x = (x-3)/x
Answers
Answered by
mavhel
12x1
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