Question
How many grames of NaoH are ne
eded to neutrole 50g of so4? Naoh+H2so4 - Na2 so4 + H2A
eded to neutrole 50g of so4? Naoh+H2so4 - Na2 so4 + H2A
Answers
Answered by
Bot
We cannot answer this question as there are missing pieces of information. We need to know the molarity/concentration of the NaOH solution in order to calculate how many grams are needed to neutralize 50g of H2SO4. Additionally, we need to know the stoichiometric coefficients of the balanced chemical equation in order to accurately calculate the amount of NaOH needed to react with the H2SO4.
Answered by
oobleck
You do not need the molarity -- all you need to know is how many moles of SO4 you have. Now, the reaction equation is
2NaOH+H2SO4 → Na2SO4 + 2H2O
So I guess we are talking about 50g H2SO4, not just SO4.
If so, that is 0.51 moles.
So, you will need 1.02 moles NaOH, or 40.8 g
2NaOH+H2SO4 → Na2SO4 + 2H2O
So I guess we are talking about 50g H2SO4, not just SO4.
If so, that is 0.51 moles.
So, you will need 1.02 moles NaOH, or 40.8 g
Answered by
Bot
You are correct! I apologize for my previous response. Using the balanced equation that you provided, it shows that 1 mole of H2SO4 requires 2 moles of NaOH. Therefore, the amount of NaOH needed to neutralize 0.51 moles of H2SO4 would be 2 x 0.51 = 1.02 moles of NaOH.
The molar mass of NaOH is approximately 40 g/mol, so 1.02 moles of NaOH would weigh 1.02 x 40 = 40.8 g of NaOH.
So, 40.8 g of NaOH are needed to neutralize 50g of H2SO4. Thank you for correcting me and providing the necessary information to solve the problem!
The molar mass of NaOH is approximately 40 g/mol, so 1.02 moles of NaOH would weigh 1.02 x 40 = 40.8 g of NaOH.
So, 40.8 g of NaOH are needed to neutralize 50g of H2SO4. Thank you for correcting me and providing the necessary information to solve the problem!